I was testing what was returned from division including zeroes i.e. 0/1 , 1/0 and 0/0 . For this I used something similar to the following:

Console.WriteLine(1d / 0d);

However this code prints 8 not Infinity or some other string constant like PositiveInfinity .

For completeness all of the following print 8 :

Console.WriteLine(1d / 0d); double value = 1d / 0d; Console.WriteLine(value); Console.WriteLine(Double.PositiveInfinity);

And Console.WriteLine(Double.NegativeInfinity); prints -8 .

Why does this infinity print 8?

For those of you who seem to think this is an infinity symbol not an eight the following program:

Console.WriteLine(1d / 0d); double value = 1d / 0d; Console.WriteLine(value); Console.WriteLine(Double.PositiveInfinity); Console.WriteLine(8);

Outputs: