Ryanair is a wonderful example of two extremes - it’s one of the worst possible airlines that nickel and dimes you for everything, it’s not a great employer, and it is rated the worst European airline; however, it’s dirt cheap.

Some friends and I wanted to take a trip out of Venice right before Christmas. We did not want to do a single round trip, though - we wanted to do a multi leg journey. The problem with Ryanair’s site, however, is that it only lets you make a single round trip itinerary. This is great for round trip flights to a single destination, but means that it’s a significant amount of work to cross reference which city goes where. If my flight plan is Airport A -> Airport B -> Airport C -> Airport A there’s no way to check that B -> C -> A is a valid journey without checking both the B -> C segment and the C -> A segment.

For instance, our first thought was to go to Berlin. Great - Ryanair has a nonstop from Venice Treviso to Berlin Schönefeld. If we want to add another leg of the trip, which then proceeds to return to Venice Treviso, we’d need to manually go through each of the airports that Berlin flies to and see if that airport flew to Venice.

We could model the relationship between airports as a graph, and then look for a cycle in the graph of size 3, with two nodes we already know.

The first step was to actually get the data from their site.

Inspecting their site

I was hoping for an XHR request that retrieved a full list of airports in JSON format. Unfortunately I wasn’t that lucky, but I got close enough. The HTML contained a lot of ng- attributes, so I knew it was an angular app. Angular will store all variables in the state of a node, so I could just extract it from there.

The front end clearly did some sort of filtering - if you selected a departure airport it would only show you available destinations. I thought I could just find the node’s state and extract it from there.

I started poking through devtools, using angular to inspect various nodes’ state. In the HTML for the destination picker there was a normal ng-repeat that iterated over a local variable allAirportsList in a destinationPicker object.

I traversed down the state tree until I found the allAirportsList property, which contained all the airport keys and the locations to which they flew. I extracted this state (over 1MB of route information) and could now build a graph representation of airport connections.

Building out a graph model

First I had to store the information in a method that would be easily parsed and converted into a graph. The easiest would be to just have a map in which every key (an airport IATA code) was a set of all the airports that it could fly to.

let mappings = {}; let airportCodes = []; for ( const airport of airports . allAirportsList ) { let id = airport . id ; //format airport:XYZ let ryanairId = id . split ( " : " ); if ( ryanairId [ 0 ] === " airport " ) { let iata = ryanairId [ 1 ]; airportCodes . push ( iata ); if ( ! mappings . hasOwnProperty ( iata )) { mappings [ iata ] = new Set (); } let routes = airport . routes . filter ( entry => { return entry . startsWith ( ' airport ' ); }); routes = routes . map ( entry => entry . split ( " : " )[ 1 ]); // Format airport:XYZ routes = routes . map ( entry => entry . split ( " | " )[ 0 ]); // Some airports have format airport:XYZ|XYZ City for ( const route of routes ) { mappings [ iata ]. add ( route ); } } }

I’m not sure if this is a bidirectional graph - I don’t know if Airport A flying to Airport B means that Airport B also flies to Airport A. For now I’ll keep this as a directed graph.

I decided to use Cytoscape to visualize the results, as I’d used the library before. This visualization will help in the final graph, as it will show all the valid airports.

Click Start Above

We could now visualize a graph of every airport and it’s destinations. This was significantly more than I was expecting - the graph is almost unusable there are so many connections (there are 4223 edges!). We’d need to filter this more to remove all airports that did not satisfy our conditions.

Click Start Above

This is a graph that only shows outgoing connections from SXF , Berlin Schönefeld. However, this shows us destinations that might not connect to TSF .

We want a list of potential cities that A) Are reachable from Berlin and B) Will fly to TSF , Venice Treviso.

We can just check each of the airports in the above graph and cross reference it with our original mappings - if TSF is not in the mapping, then we can remove it and all it’s edges from the graph.

Click Start Above

And there we have our graph! All valid connections that go TSF -> SXF -> ??? -> TSF .

The best part of this is that all the above airports fly to TSF - we can add many more airports to our trip this way. We know that any path in the graph above lets us return to TSF , which means we can do a trip with N many distinct stops, where N is the length of the longest non repeating path!

We can also run a Depth First Search from SXF to compute the full path to every node.

Path

Deciding on cities

The graphs above are a cool visual representation but our end goal is really just a list of possible voyages - something like TSF -> SXF -> MLA -> TSF . The full list is here:

AGP - Malaga, Spain

BRI - Bari, Italy

BRU - Brussels, Belgium

BUD - Budapest, Hungary

CGN - Cologne, Germany

CTA - Catania, Italy

DUB - Dublin, Ireland

EDI - Edinburgh, United Kingdom

EMA - East Midlands, United Kingdom

KRK - Krakow, Poland

LPA - Gran Canaria, Spain

MAN - Manchester, United Kingdom

MLA - Malta, Malta

OPO - Porto, Portugal

PMO - Palermo, Italy

RAK - Marrakesh, Morocco

SOF - Sofia, Bulgaria

STN - London Stansted, United Kingdom

SVQ - Seville, Spain

SXF - Berlin Schönefeld, Germany

TFS - Tenerife South, Spain

VLC - Valencia, Spain

VNO - Vilnius, Lithuania

Cycles, NP-Complete-ness, and arbitrary airports

I thought it would be fun to see if we could actually find a Hamiltonian Cycle in the graph. Unfortunately, with 242 airports and over 4000 routes this would be nearly impossible to compute. It’s actually not that bad to find it in the final graph below, though - although it is NP-Complete, when a graph is as connected with as many edges as above it’s actually not that difficult to find.

I also wrote the tool below to compute cycles up to 4 airports in length, starting and ending from a set airport.

Number of Additional Stops 1 2 3 4 (Slow!) 5 (Slower!) 6 (Slowest - Probably shouldn't use this!) Start

End

Conclusion

This was the first time I’ve used a graph algorithm in a non-academic context, which is pretty cool. It was a fun endeavour that created a tool that will hopefully be useful to some. If you’re looking to plan a super cheap European vacation you can just use this to add all the legs of your Ryanair flights!

A nice future addition would be to somehow get price data for each flight plan. I found their API and it’s pretty straight forward:

curl 'https://api.ryanair.com/farefinder/3/oneWayFares?&departureAirportIataCode=TSF&language=en&limit=16&market=en-gb&offset=0&outboundDepartureDateFrom=2018-10-04&outboundDepartureDateTo=2019-10-26&priceValueTo=150'

I might get to that if I find that our N-length trip gets too expensive.

Also I apologize if this webpage was slow or clunky - normally I’m a huge fan of web optimizations, but this blog post needed libraries that are significantly slower than average to show what I wanted to show.