Bash Special Parameters Explained with 4 Example Shell Scripts

As part of our on-going bash tutorial series, we discussed about bash positional parameters in our previous article. In this article let us discuss about the bash special parameters with few practical shell script examples.

Some of the bash special parameters that we will discuss in this article are: $*, $@, $#, $$, $!, $?, $-, $_



To access the whole list of positional parameters, the two special parameters $* and $@ are available. Outside of double quotes, these two are equivalent: Both expand to the list of positional parameters starting with $1 (separated by spaces).

Within double quotes, however, they differ: $* within a pair of double quotes is equivalent to the list of positional parameters, separated by the first character of IFS “$1c$2c$3…”.

$@ within a pair of double quotes is equivalent to the list of positional parameters, separated by unquoted spaces, i.e., “$1” “$2″..”$N”.

Example 1: Use Bash $* and $@ to Expand Positional Parameters

This example shows the value available in $* and $@.

First, create the expan.sh as shown below.

$ cat expan.sh #!/bin/bash export IFS='-' cnt=1 # Printing the data available in $* echo "Values of \"\$*\":" for arg in "$*" do echo "Arg #$cnt= $arg" let "cnt+=1" done cnt=1 # Printing the data available in $@ echo "Values of \"\$@\":" for arg in "$@" do echo "Arg #$cnt= $arg" let "cnt+=1" done

Next, execute the expan.sh as shown below to see how $* and $@ works.

$ ./expan.sh "This is" 2 3 Values of "$*": Arg #1= This is-2-3 Values of "$@": Arg #1= This is Arg #2= 2 Arg #3= 3

The above script exported the value of IFS (Internal Field Separator) with the ‘-‘.

There are three parameter passed to the script expan.sh $1=”This is”,$2=”2″ and $3=”3″.

When printing the each value of special parameter “$*”, it gives only one value which is the whole positional parameter delimited by IFS.

Whereas “$@” gives you each parameter as a separate word.

Example 2: Use $# to Count Positional Parameters

$# is the special parameter in bash which gives you the number of positional parameter in decimal.

First, create the arithmetic.sh as shown below.

$ cat arithmetic.sh #!/bin/bash if [ $# -lt 2 ] then echo "Usage: $0 arg1 arg2" exit fi echo -e "\$1=$1" echo -e "\$2=$2" let add=$1+$2 let sub=$1-$2 let mul=$1*$2 let div=$1/$2 echo -e "Addition=$add

Subtraction=$sub

Multiplication=$mul

Division=$div

"

If the number of positional parameters is less than 2, it will throw the usage information as shown below,

$ ./arithemetic.sh 10 Usage: ./arithemetic.sh arg1 arg2

Example 3: Process related Parameters – $$ and $!

The special parameter $$ will give the process ID of the shell. $! gives you the process id of the most recently executed background process.

The following script prints the process id of the shell and last execute background process ID.

$ cat proc.sh #!/bin/bash echo -e "Process ID=$$" sleep 1000 & echo -e "Background Process ID=$!"

Now, execute the above script, and check the process id which its printing.

$ ./proc.sh Process ID=9502 Background Process ID=9503 $ ps PID TTY TIME CMD 5970 pts/1 00:00:00 bash 9503 pts/1 00:00:00 sleep 9504 pts/1 00:00:00 ps $

Example 4: Other Bash Special Parameters – $?, $-, $_

$? Gives the exit status of the most recently executed command.

Gives the exit status of the most recently executed command. $- Options set using set builtin command

Options set using set builtin command $_ Gives the last argument to the previous command. At the shell startup, it gives the absolute filename of the shell script being executed.

$ cat others.sh #!/bin/bash echo -e "$_"; ## Absolute name of the file which is being executed /usr/local/bin/dbhome # execute the command. #check the exit status of dbhome if [ "$?" -ne "0" ]; then echo "Sorry, Command execution failed !" fi echo -e "$-"; #Set options - hB echo -e $_ # Last argument of the previous command.

In the above script, the last echo statement “echo -e $_” ($ underscore) also prints hB which is the value of last argument of the previous command. So $_ will give the value after expansion

$ ./others.sh ./others.sh /home/oracle Sorry, Command execution failed ! hB hB

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