These topics come up perennially in std-proposals, StackOverflow, and other places where us C++ types hang out. I thought I’d collect them all in one place.

Detect the first argument type of a function

We can easily write a type-based metafunction first_arg_type_t<F> such that for example first_arg_type_t<void(int,double)> is int and first_arg_type_t<void (A::*)(B&)> is B& (or, if you prefer, A* ).

We can even extend this to lambdas with a tiny bit of hackery.

So people inevitably try to build APIs where they receive an arbitrary Callable and then deduce what kind of arguments it wants to be passed.

template<class F> void MyFuture::then(F&& f) { if constexpr (first_argument_type_is<F, MyFuture>) { return F(*this); } else { return F(this->value); } }

This is just possible enough to get people in trouble.

Where it breaks down is when you have a generic lambda, or a function-like object with several overloaded operator() s (such as separate const and non- const versions), or a function template or overload set in general.

If (as in this case) you’re trying to decide how to call the function, you also have to watch out for cvref-qualification — what should you do if you wanted the first argument type to be MyFuture but the user gave you a function that takes const MyFuture& ? And implicit conversions — what if you wanted a function taking int but the user gave you one taking long ?

The solution is to not do that. In our snippet above, we should have created two member functions, perhaps then_f and then_v , where the first unconditionally returns F(*this) and the second unconditionally returns F(this->value) . Just let the user call the one they want!

string_view versions of many utility functions

In C++11 we got std::stoi(const std::string&) , which is just a super convenient wrapper around strtol .

In C++17 we got std::string_view , which is a super convenient replacement for const std::string& as a function parameter.

So where’s my std::svtoi(std::string_view) ?

Well, you’ll get that exactly as soon as C provides a memtol function that can turn an arbitrary non-null-terminated range of chars into an integer. Because nobody involved with C++ wants to reimplement string-to-int conversion just in order to make it work with non-null-terminated strings. (Except of course when they do.)

Similarly, you’ll get fopen(std::string_view) just as soon as the POSIX open syscall starts accepting non-null-terminated strings. Which is to say, never.

Detect the constexprness of the current context

Today, we have a classic tradeoff: “Fast at runtime, or callable at compile-time: pick one.”

Consider sqrt . This C++14 code is modeled on Alex Shtof’s C++11 version.

// Compiled with -ffast-math, this produces 95 bytes of code. // sqrtsd %xmm0, %xmm0 ; ret constexpr double constexpr_sqrt(double x) { if (0 <= x && x < std::numeric_limits<double>::infinity()) { double curr = x; double prev = 0; while (curr != prev) { prev = curr; curr = 0.5 * (curr + x / curr); } return curr; } else { return std::numeric_limits<double>::quiet_NaN(); } } double nonconstexpr_sqrt(double x) { return __builtin_sqrt(x); }

The codegen for constexpr_sqrt (assuming you’ve got at least one call to it with a non-compile-time-constant argument) is 23 instructions (and 4 branches) long, even with -O3 -ffast-math . The codegen for nonconstexpr_sqrt , under the same conditions, is two instructions long:

sqrtsd %xmm0, %xmm0 ret

So wouldn’t it be cool if we could somehow branch on whether the constexpr version was needed in the current context?

constexpr double optionally_constexpr_sqrt(double x) { if constexpr (constexpr()) { if (0 <= x && x < std::numeric_limits<double>::infinity()) { double curr = x; double prev = 0; while (curr != prev) { prev = curr; curr = 0.5 * (curr + x / curr); } return curr; } else { return std::numeric_limits<double>::quiet_NaN(); } } else { return __builtin_sqrt(x); } }

(That example uses Daveed Vandevoorde’s original syntax from P0595R0, which underwent severe changes in P0595R1.)

This is great, right? It’s basically Perl’s wantarray builtin, except that instead of telling you about the way your function’s result is going to be used, it… wait, never mind, that’s exactly what it does.

So it seems like we can have some fun with this.

constexpr auto silly() { if constexpr (constexpr()) { return (int*)nullptr; } else { return (double*)nullptr; } } void foo() { decltype(silly()) x = silly(); }

The silly() inside the decltype is clearly a constexpr context — okay, actually the function isn’t evaluated at all, but let’s call it a constexpr context — so we get int *x = silly() . But then the right-hand side has no reason to prefer compile-time evaluation, so it gives back a double* , and we get a compile-time error.

Alternatively,

struct Evil { constexpr Evil(double*) {} Evil(int*) {} }; Evil bar = silly();

This static-lifetime initializer prefers to be constexpr, if it can. So it evaluates silly() in constexpr context and gets int* … which it can’t use constexprly itself! So maybe it promotes bar ’s initialization to runtime; or maybe it backtracks and re-evaluates silly() in non-constexpr context, gets a double* , and proceeds to initialize bar at compile-time after all.

P0595R1 has some discussion of this kind of issue, particularly focused on issues around template instantiations that might be triggered by the backtracking, which P0595R1 calls “tentative constant evaluation.”

(UPDATE: Barry Revzin points out that under P0595R1, the thing-formerly-known-as- constexpr() actually looks only at its immediately enclosing context; so all of my if constexpr (constexpr()) branches are actually asking about the constexprness of the if constexpr condition itself, and therefore are all equivalent to if constexpr (true) . This seems to eliminate some of these metaprogramming-related issues, although it does mean that both branches must be instantiable even in the constexpr case.)

Strong typedefs

C++’s typedefs are notoriously weak. So weak, in fact, that we’re not supposed to call them “typedefs” anymore. Since C++11, we call them “type aliases.” Thinking of type aliases as type definitions can really get you into trouble.

using AltitudeAboveMeanSeaLevel = int; void fly_at(AltitudeAboveMeanSeaLevel h); using HeightAboveGroundLevel = int; HeightAboveGroundLevel lowest_safe_altitude(); static void cfit() { fly_at(lowest_safe_altitude()); }

And the standard library isn’t helping, with its zoo of synonyms for built-in types. Sergey Ignatchenko gives an example where f is overloaded for all four of int8_t , int16_t , int32_t , and int64_t , and yet a simple call to f(0) does not compile.

So, wouldn’t it be cool if we had strong type definitions in C++? Yes, it would. The problem is that the API of a type is more than just its member functions (or, in the case of primitive types, more than just its built-in operators). Consider the following semi-realistic C++ class:

struct Widget { int data; void swap(Widget&) noexcept; friend void foo(); friend bool operator==(const Widget& a, const Widget& b) noexcept { return a.data == b.data; } }; void swap(Widget& a, Widget& b) noexcept { return a.swap(b); } bool operator!= (const Widget& a, const Widget& b) noexcept { return !(a == b); } template<> struct std::hash<Widget> { size_t operator()(const Widget& w) const { return std::hash<int>()(w.data); } }; void replace_if_possible(std::vector<Widget>& haystack, const Widget& needle); std::unique_ptr<Widget> make_widget(); std::unordered_set<Widget> wset;

Now we suppose that C++ magically gains “strong typedefs,” and we write:

strong_typedef Gadget = Widget; Gadget g, h; std::vector<Gadget> gv;

Now go down the following list. Answer “yes” or “no” to each question. You can stop at the first “no” if you want.

A: Can we refer to g.data ? (We’d better be able to, right?)

? (We’d better be able to, right?) B: Does g.swap(h) compile?

compile? C: What about swap(g, h) ?

? D: Is void foo() a friend of Gadget ?

a friend of ? E: Does the template specialization std::hash<Gadget> exist?

exist? F: Does g == h compile?

compile? G: Does g != h compile?

compile? H: Is std::unordered_set<Gadget> instantiable?

instantiable? I: Does replace_if_possible(gv, g) compile?

compile? J: Does auto p = make_gadget() compile?

compile? K: Can we refer to gset ?

If you answered “yes” to B, can you explain why the argument type of g.swap(...) is apparently Gadget& and not its declared type Widget& ?

If you said “yes” on C but “no” on G: why?

If you said “no” to either of E or F but “yes” to H: you’re wrong.

If you said “yes” to G: Would your answer still be “yes” if operator!= had been merely declared, not defined? What if its body was defined in some other .cpp file entirely? What if that .cpp file didn’t contain the strong_typedef declaration?

If you said “yes” to J or K: Okay, so, ten out of ten for style, but…

And finally, if you said “no” to all of B, C, D, E, F, G, and H: you haven’t really got a strong “typedef” anymore. It’s more like you just made a completely new type, lacking the basic amenities such as equality comparison, swappability, and hashability.

Any proposal for strong typedefs has got to somehow deal with the very messy question of how to determine the “API” of a C++ type.