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I've an old device whose circuit is fried somewhere but since I want to modify this device, I don't want to find which component is fried, I simply want to plug it my own power supply instead. Luckily I have a second working device to test voltage and current wherever I want.

This device has a tiny coil activating a switch when current passes through it so I desoldered the wires on the working device to test this component. I tested both in DC and AC mode, here are the results:

Resistance: 64 Ohms

Voltage: OL (DC) 2.1 V (AC)

Current: Entering the coil: 177 mA ( DC ) and 31 mA ( AC ) Leaving the coil: 177 mA ( DC ) and 31 mA ( AC ) then slowly lowering to 30 mA ( AC )



My question is: Can I deduce for sure this is an AC coil requiring an input of 2.1 V and 31 mA?

Also I know that assuming this is an AC coil I should in theory be able to input DC current as well. This way would be much more convenient since phone chargers or other kinds of everyday life transformers are often providing DC current.

So what would be the input power like if I choose to input DC instead of AC (assuming this coil is really an AC coil)? Is there an easy way to calcule the voltage and current I should apply?

EDIT: Additional information about the coil

Here is a photo of the coil. When a current passes through it, a magnetic field is created therefore attracting the metal plate. When this happens it activates a mechanical system which uses rotational energy from a 230V AC motor.