Not exactly accurate. Depends on how it's wired (series vs parallel).

@reddog92396 - If you make another set of 2 batteries, wired exactly like the first set of 2, then wire those 2 sets in parallel, rather than series, you will retain the same ~3V, but double your amperage. But, that may not solve your problem (read on)



While i have no intention of offending or disparaging the author, the following should address many of the issues other people seem to be having, as well as a glaring failure on the author's part to include obligatory and necessary information:

It's very important to accurately provide the needed voltage, which is usually NOT going to be a direct multiple of 1.5V. Additionally, you must provide the necessary amperage (somewhat blindly addressed by the author). Most cell phones will have the ability to handle slight over-voltages (note: i said: SLIGHT); they do this with resistors on the power inputs. These resistors can only handle small over-voltages, because they are SMD (physically small, thus, electrical capacity is small). You'll need to stack your batteries (AA, AAA, C, D, whatever) in such a way as to provide a voltage slightly over the listed battery voltage, then use a resistor to drop it back down to the exact required voltage. This assumes you are using alkaline batteries... Rechargeable batteries behave a little differently as they discharge, and rarely get above their listed voltage, thus, a slight difference in voltage will likely not create a problem. i'm not going to give you the values for the resistors, because there are already online tools for that, and there's no way i'd be able to provide the exact values for every single cell phone and battery combination. For those that are having amperage issues (it turns on, but you can't call): add more batteries in parallel, NOT series. This will boost your available power without changing your voltage.