

Click here to see ALL problems on Miscellaneous Word Problems Question 451028: the force exerted by the wind on a plane surface varies directly with the area of the surface and the square of the velocity of the wind. If the force on an area of 20 square feet is 11 pounds when the wind velocity is 22 miles per hour, find the force on a surface area of 47.125 square feet when the wind velocity is 36.5 miles per hour.

Answer by ankor@dixie-net.com(22142) (Show Source):



of the surface and the square of the velocity of the wind.

If the force on an area of 20 square feet is 11 pounds when the wind velocity is 22 miles per hour, find the force on a surface area of 47.125 square feet when the wind velocity is 36.5 miles per hour.

:

Find the constant of variation (k):

"the force on an area of 20 sq/ft is 11 pounds when the wind velocity is 22 mph"

20*22^2*k = 11

9680k = 11

k =

k = .00113636

:

find the force (f) on a surface area of 47.125 square feet when the wind velocity is 36.5 miles per hour.

f = s.a * wind vel^2 * k

f = 47.125 * 36.5^2 * .00113636

f = 47.125 * 1332.25 * .00113636

f = 71.34 lbs the force exerted by the wind on a plane surface varies directly with the areaof the surface and the square of the velocity of the wind.If the force on an area of 20 square feet is 11 pounds when the wind velocity is 22 miles per hour, find the force on a surface area of 47.125 square feet when the wind velocity is 36.5 miles per hour.Find the constant of variation (k):"the force on an area of 20 sq/ft is 11 pounds when the wind velocity is 22 mph"20*22^2*k = 119680k = 11k =k = .00113636find the force (f) on a surface area of 47.125 square feet when the wind velocity is 36.5 miles per hour.f = s.a * wind vel^2 * kf = 47.125 * 36.5^2 * .00113636f = 47.125 * 1332.25 * .00113636f = 71.34 lbs You can put this solution on YOUR website!

