Stock picture: A woman in India lost 10 babies to miscarriage in one night (not pictured) (Picture: Getty Images)

A woman in India has lost ten babies to miscarriage in one night.

Anju Kushwaha, 28, from the Satna district of the Madhya Pradesh province, suffered the miscarriage 12 weeks into her pregnancy.

She delivered nine babies late on Sunday night before she travelled 77 miles (125K) to the nearest hospital where she delivered the tenth infant.

Her husband Sanjay was carrying the nine wrapped in a piece of cloth when they arrived.


Dr SK Pathak, assistant superintendent of the hospital said: ‘She delivered nine of them midway. Obstetric and NICU team at our hospital helped her to deliver the tenth one in the operation theatre – all were born dead at almost 12 weeks.’



Doctors say Mrs Kushwaha experienced an extreme form of a condition known as multifetal pregnancy, which usually produces twins or even triplets.

However, it is also been confirmed that she underwent fertility treatment, which maybe have contributed to the unusually high number of foetuses

Senior gynaecologist, Dr Sumitra Yadav said: ‘It seems that that there was no regular follow-up of her pregnancy after IVF. At least three offspring could have been saved by reducing the pregnancy.’

The case marks the highest number of babies in a womb ever recorded in India, and the second highest in the world.

In 1971, a doctor in Rome claimed to have delivered 15 babies at once, however none of them survived.

Note: This article originally stated the woman gave birth to ten stillborn children, it has since been amended.