Accessing variables that need synchronization necessitates book keeping by programmers. Since it is not something explicitly enforced by the language mechanics, programmer needs to make sure that such variables are not accessed out of a synchronization scope. Consider the following innocent user store:

case class User ( id : Int , name : String , manager : Boolean ) // Use with caution! Can be accessed by multiple threads. private var users : Map [ Int , User ] = Map [ Int , User ]()

The safest approach would be encapsulating every access to users variables in a synchronized block:

def save ( user : User ) : Unit = synchronized { users += user . id -> user } def findById ( id : Int ) : Option [ User ] = synchronized { users . get ( id ) }

You can even go further and use a ReadWriteLock to boost read-only queries:

private val lock : ReadWriteLock = new ReentrantReadWriteLock () def save ( user : User ) : Unit = { lock . writeLock (). lock () try { users += user . id -> user } finally { lock . writeLock (). unlock () } } def findById ( id : Int ) : Option [ User ] = { lock . readLock (). lock () try { users . get ( id ) } finally { lock . readLock (). unlock () } }

Now you think you are safe. And it does not take a couple of VCS commits for somebody (most probably you) to mess up the entire synchronization scheme:

// Violating thread-safety on `users`. override def toString : String = s "There are ${users.size} user(s)."

Oops! There can arise a lot more complicated subtle bugs. Shit can even hit the fan when you introduce multiple variables or make nested calls, that is, functions calling functions calling functions which are accessing users . It is obvious that you are doomed. Now good luck with your chasing the Heisenbug journey!

Then it occured to me, can’t we make the compiler enforce a certain lock context while accessing to a particular set of variables? What if compiler would not allow you to read users if your thread did not already acquire lock.readLock() ? Or similarly would not allow you to mutate it if you did not already acquire lock.writeLock() ? Here is the solution that I came up with to these questions:

import java.util.concurrent.locks.Lock import java.util.concurrent.locks.ReentrantReadWriteLock trait SynchronizedAccess { import SynchronizedAccess._ protected val instanceLock : ReentrantReadWriteLock = new ReentrantReadWriteLock () protected val instanceReadLock : ReadLock = new ReadLock ( instanceLock . readLock ()) protected val instanceReadWriteLock : ReadWriteLock = new ReadWriteLock ( instanceLock . readLock (), instanceLock . writeLock ()) protected case class Synchronized [ T ]( private var value : T ) { def apply ()( implicit readLock : ReadLock ) : T = { validateLock ( readLock , instanceReadLock , instanceReadWriteLock ) value } def update ( newValue : T )( implicit readWriteLock : ReadWriteLock ) : Unit = { validateLock ( readWriteLock , instanceReadWriteLock ) value = newValue } private def validateLock ( lock : TypedLock , allowedLocks : TypedLock* ) : Unit = { require ( allowedLocks . contains ( lock ), "cannot be accessed from another synchronization scope" ) require ( lock . tryLock (), "cannot be accessed out of a synchronization scope" ) lock . unlock () } } protected def synchronizeRead [ T ]( body : ReadLock => T ) : T = synchronizeOperation ( instanceReadLock )( body ) protected def synchronizeReadWrite [ T ]( body : ReadWriteLock => T ) : T = synchronizeOperation ( instanceReadWriteLock )( body ) protected def synchronizeOperation [ T , L <: TypedLock ]( lock : L )( body : L => T ) : T = { lock . lock () try { body ( lock ) } finally { lock . unlock () } } } object SynchronizedAccess { sealed trait TypedLock { protected val instance : Lock def lock () : Unit = instance . lock () def unlock () : Unit = instance . unlock () def tryLock () : Boolean = instance . tryLock () } sealed class ReadLock ( readLock : ReentrantReadWriteLock.ReadLock ) extends TypedLock { override protected val instance : Lock = readLock } sealed class ReadWriteLock ( readLock : ReentrantReadWriteLock.ReadLock , writeLock : ReentrantReadWriteLock.WriteLock ) extends ReadLock ( readLock ) { override protected val instance : Lock = writeLock } }

Looks complicated? See me while I dance with it:

class UserService extends SynchronizedAccess { private val users : Synchronized [ Map [ Int , User ]] = Synchronized ( Map [ Int , User ]()) private val managerCount : Synchronized [ Int ] = Synchronized ( 0 ) def save ( user : User ) : Unit = // Note that `users` and `managerCount` variables will be updated // atomically while the rest waits for the `ReadWrite` lock. synchronizeReadWrite { implicit lock => users () += user . id -> user if ( user . manager ) managerCount () += 1 } def findById ( id : Int ) : Option [ User ] = synchronizeRead { implicit lock => users (). get ( id ) } def findAllNames () : Seq [ String ] = synchronizeRead { implicit lock => findAll . map ( _ . name ) } // Note that findAll() requires a `ReadLock` context in order to access `users`. private def findAll ( implicit lock : ReadLock ) : Seq [ User ] = users (). values . toSeq def findManagerCount () : Int = synchronizeRead { implicit lock => managerCount () } }

In a nutshell, what did SynchronizedAccess trait really bring us? It enforces a typed and unique locking context on the variables of type Synchronized[T] . It is typed because read and read-write operations are distinct from each other in the function decleration via implicit ReadLock and ReadWriteLock parameters. It is unique because Synchronized variables can only be accessed by the instance lock inherited from SynchronizedAccess trait.

Here is your free lunch. Eet smaaklijk!

Common Confusions

I sadly observed that there are some common confusions about Synchronized[T] type. Let me try to address them here.