Debian Project Leader Elections 2012

Nomination period: Sunday, March 4th 00:00:00 UTC, 2012 Saturday, March 10th 23:59:59 UTC, 2012 Campaigning period: Sunday, March 11th 00:00:00 UTC, 2012 Saturday, March 31st 23:59:59 UTC, 2012 Voting period: Sunday, April 1st, 00:00:00 UTC, 2012 Saturday, April 14th, 23:59:59 UTC, 2012

Please note that the new term for the project leader shall start on April 17th, 2012.

This year, like always, statistics will be gathered about ballots received and acknowledgements sent periodically during the voting period. Additionally, the list of voters will be recorded. Also, the tally sheet will also be made available to be viewed. Please remember that the project leader election has a secret ballot, so the tally sheet will be produced with the hash of the alias of the voter rather than the name; the alias shall be sent to the corresponding voter along with the acknowledgement of the ballot so that people may verify that their votes were correctly tabulated. While the voting is open the tally will be a dummy one; after the vote, the final tally sheet will be put in place. Please note that for secret ballots the md5sum on the dummy tally sheet is randomly generated, as otherwise the dummy tally sheet would leak information relating the md5 hash and the voter.

With the current list of voting developers, we have:

Current Developer Count = 948 Q ( sqrt(#devel) / 2 ) = 15.3948043183407 K min(5, Q ) = 5 Quorum (3 x Q ) = 46.184412955022

Quorum

Option1 Reached quorum: 310 > 46.184412955022

Option2 Reached quorum: 281 > 46.184412955022

Option3 Reached quorum: 385 > 46.184412955022

All candidates would need a simple majority to be eligible.

Majority

Option1 passes Majority. 5.167 (310/60) >= 1

Option2 passes Majority. 3.603 (281/78) >= 1

Option3 passes Majority. 32.083 (385/12) >= 1

In the graph above, any pink colored nodes imply that the option did not pass majority, the Blue is the winner. The Octagon is used for the options that did not beat the default.

Option 1 "Wouter Verhelst"

Option 2 "Gergely Nagy"

Option 3 "Stefano Zacchiroli"

Option 4 "None Of The Above"

In the following table, tally[row x][col y] represents the votes that option x received over option y. A more detailed explanation of the beat matrix may help in understanding the table. For understanding the Condorcet method, the Wikipedia entry is fairly informative.

The Beat Matrix Option 1 2 3 4 Option 1 203 37 310 Option 2 97 34 281 Option 3 347 354 385 Option 4 60 78 12

Looking at row 2, column 1, Gergely Nagy

received 97 votes over Wouter Verhelst



Looking at row 1, column 2, Wouter Verhelst

received 203 votes over Gergely Nagy.



Pair-wise defeats

Option 1 defeats Option 2 by ( 203 - 97) = 106 votes.

Option 3 defeats Option 1 by ( 347 - 37) = 310 votes.

Option 1 defeats Option 4 by ( 310 - 60) = 250 votes.

Option 3 defeats Option 2 by ( 354 - 34) = 320 votes.

Option 2 defeats Option 4 by ( 281 - 78) = 203 votes.

Option 3 defeats Option 4 by ( 385 - 12) = 373 votes.

The Schwartz Set contains

Option 3 "Stefano Zacchiroli"

The winners

Option 3 "Stefano Zacchiroli"