Indians ace Corey Kluber was named AL Player of the Week after going 1–0 with a 0.00 ERA across 16.0 innings with just two walks and 24 strikeouts in two starts last week. He worked his fifth career complete-game shutout last Monday at Baltimore, holding the Orioles to just three hits with no walks and 11 strikeouts in Cleveland’s 12–0 win. A few days later, the Tribe’s ace struck out season-high 13 batters Saturday against Minnesota, holding the Twins to two unearned runs and three hits across seven innings.

Since returning from the Disabled List on June 1, he has gone an undefeated 3–0 with a 1.29 ERA while holding opponents to a .157 average with 52 strikeouts. Kluber has struck out 10 or more batters in three straight games, which ties the longest streak of his career and is one game shy of tying Bob Feller for the longest streak in Indians history.

This marks his third career Player of the Week award with the last coming in September of his 2014 Cy Young Award season.