OK, this is going to get complicated, so try and follow along.

"illuminati" can be rearranged to spell "i mill i tuna", implying that all tuna work at mills. However, this is not actually true. As everyone knows, the only way to successfully translate from tuna to English is to go through google translator 50 times. For this i will use the website bad translator. Many people think that this website is a joke, only a select few actually know its true purpose: to unlock the mind of a tuna, via its language.

But i digress.

Back to the point, "i mill i tuna" through the secret decoder (bad translator) is "Tuna and Avocado" As everyone knows, A is the area of something. In this case, it is the area of an average tuna. To get this size, we will average out the smallest tuna (about 0.5m in length) and the largest tuna (4.6m in length)

(0.5+4.6)/2 = 2.55m is the average length of a tuna.

Following this same logic, the average width of a tuna would be approximately equal to 0.446m.

assuming that a tuna is roughly ellipsoid in shape, its surface area would be equal to 7.26m^2. Therefore every instance of A should be replaced by 11.64m^2

This leaves us with "tun(11.64m^2)+(11.64m^2)nd+2(11.64m^2)vocdo" which is the same as

(11.64m^2)(tun+nd+4vocd)

c is a constant, the speed of light (for simplicities sake we will say this is 3.00X10^8 m/s)

since v is velocity, we can again do our tuna calculations to find the average for an average tuna. Using a similar equation to above, we can conclude that the average swim speed of a tuna is 6.9m/s. n is the index of refraction in water (where the tuna live) = 1.333

The element Uut is element #113. this means that ut=113/u, and u = 113/ut = 113/113 = 1

Since the element Cd has # = 48, and c = 3.00x10^8,

therefore d = 48/3.00x10^8m/s = 0.00000016s/m.

Our final equation is

illuminati = (11.64m^2)[(113)(1.333) + 1.333(0.00000016s/m) + 4(6.9m/s)(0)(48)

= 11.64m^2(150.629 + 0.000000213s/m)

= 1753.321562ms

if we assign each letter of the alphabet to a numberical value starting with A=1, B=2, ect, then 1753321562, separated like 1 7 5 3 3 2 15 5 6 2 then we get, as alphabetical values, AHECCBOEFB. Another obvious anagram, this time for "Boba Fecech" and obvious misspelling of "Boba Fett", the famed bounty hunter. now, if we revert "Boba Fett" back into numbers via the A=1 formula, then we have 21521 651919.

The answer to your original question should now be obvious, but if you do not see it here is some more help. If you arrange the numbers we have in descending order, we get 99655221111.

we will start with the ones. 111+1 = 112. 11+2 = 13. 1x3 = 3. therefore 1111 = 3.

now the two's. this one is simple. since there are two of them, 22 simply = 2.

Next, we have 99655. This one is a bit trickier. since there are two numbers repeated twice, 99 = 22 and 55 = 22. we already stated that 22 = 2, so we are left with 262. since a 6 is an upside down nine, 6 = 1/9 therefore 6 = 1/(22/2) = 1/11 = 1 (since the one on the bottom cancels with the one on the top, ;leaving you with 1/1 which is = to 1) therefore 99655 = 212. we are no left with 212 and 3. in the absence of an operation, assume multiplication (for example, (x)(y) is xy not x+y)

(212)(3) = (2(1+2))(3) = 23(3) = 69.

QED