Warning: This blog post is outdated. Instead, please read chapter “Prototype chains and classes” of “JavaScript for impatient programmers” .

Recently, TC39 decided on the final semantics of classes in ECMAScript 6 . This blog post explains how their final incarnation works. The most significant recent changes were related to how subclassing is handled.

class Point { constructor (x, y) { this .x = x; this .y = y; } toString() { return '(' + this .x + ', ' + this .y + ')' ; } } class ColorPoint extends Point { constructor (x, y, color) { super (x, y); this .color = color; } toString() { return super .toString() + ' in ' + this .color; } } let cp = new ColorPoint( 25 , 8 , 'green' ); cp.toString(); console .log(cp instanceof ColorPoint); console .log(cp instanceof Point);

The essentials #

Base classes #

A class is defined like this in ECMAScript 6 (ES6):

class Point { constructor (x, y) { this .x = x; this .y = y; } toString() { return '(' + this .x + ', ' + this .y + ')' ; } }

You use this class just like an ES5 constructor function:

> var p = new Point(25, 8); > p.toString() '(25, 8)'

In fact, the result of a class definition is a function:

> typeof Point 'function'

However, you can only invoke a class via new , not via a function call (Sect. 9.2.2 in the spec):

> Point() TypeError: Classes can’t be function-called

Class declarations are not hoisted #

Function declarations are hoisted: When entering a scope, the functions that are declared in it are immediately available – independently of where the declarations happen. That means that you can call a function that is declared later:

foo(); function foo ( ) {}

In contrast, class declarations are not hoisted. Therefore, a class only exists after execution reached its definition and it was evaluated. Accessing it beforehand leads to a ReferenceError :

new Foo(); class Foo {}

The reason for this limitation is that classes can have an extends clause whose value is an arbitrary expression. That expression must be evaluated in the proper “location”, its evaluation can’t be hoisted.

Not having hoisting is less limiting than you may think. For example, a function that comes before a class declaration can still refer to that class, but you have to wait until the class declaration has been evaluated before you can call the function.

function functionThatUsesBar ( ) { new Bar(); } functionThatUsesBar(); class Bar {} functionThatUsesBar();

Class expressions #

Similarly to functions, there are two kinds of class definitions, two ways to define a class: class declarations and class expressions.

Also similarly to functions, the identifier of a class expression is only visible within the expression:

const MyClass = class Me { getClassName() { return Me.name; } }; let inst = new MyClass(); console .log(inst.getClassName()); console .log(Me.name);

Inside the body of a class definition #

A class body can only contain methods, but not data properties. Prototypes having data properties is generally considered an anti-pattern, so this just enforces a best practice.

constructor , static methods, prototype methods #

Let’s examine three kinds of methods that you often find in class literals.

class Foo { constructor (prop) { this .prop = prop; } static staticMethod() { return 'classy' ; } prototypeMethod() { return 'prototypical' ; } } let foo = new Foo( 123 );

The object diagram for this class declaration looks as follows. Tip for understanding it: [[Prototype]] is an inheritance relationship between objects, while prototype is a normal property whose value is an object. The property prototype is only special because the new operator uses its value as the prototype for instances it creates.

First, the pseudo-method constructor . This method is special, as it defines the function that represents the class:

> Foo === Foo.prototype.constructor true > typeof Foo 'function'

It is sometimes called a class constructor . It has features that normal constructor functions don’t have (mainly the ability to constructor-call its super-constructor via super() , which is explained later).

Second, static methods. Static properties (or class properties) are properties of Foo itself. If you prefix a method definition with static , you create a class method:

> typeof Foo.staticMethod 'function' > Foo.staticMethod() 'classy'

Third, prototype methods. The prototype properties of Foo are the properties of Foo.prototype . They are usually methods and inherited by instances of Foo .

> typeof Foo.prototype.prototypeMethod 'function' > foo.prototypeMethod() 'prototypical'

Getters and setters #

The syntax for getters and setters is just like in ECMAScript 5 object literals:

class MyClass { get prop() { return 'getter' ; } set prop(value) { console .log( 'setter: ' +value); } }

You use MyClass as follows.

> let inst = new MyClass(); > inst.prop = 123; setter: 123 > inst.prop 'getter'

Computed method names #

You can define the name of a method via an expression, if you put it in square brackets. For example, the following ways of defining Foo are all equivalent.

class Foo { myMethod() {} } class Foo { [ 'my' + 'Method' ]() {} } const m = 'myMethod' ; class Foo { [m]() {} }

Several special methods in ECMAScript 6 have keys that are symbols . Computed method names allow you to define such methods. For example, if an object has a method whose key is Symbol.iterator , it is iterable . That means that its contents can be iterated over by the for-of loop and other language mechanisms.

class IterableClass { [ Symbol .iterator]() { ··· } }

Generator methods #

If you prefix a method definition with an asterisk ( * ), it becomes a generator method . Among other things, a generator is useful for defining the method whose key is Symbol.iterator . The following code demonstrates how that works.

class IterableArguments { constructor (...args) { this .args = args; } * [ Symbol .iterator]() { for ( let arg of this .args) { yield arg; } } } for ( let x of new IterableArguments( 'hello' , 'world' )) { console .log(x); }

The extends clause lets you create a subclass of an existing constructor (which may or may not have been defined via a class):

class Point { constructor (x, y) { this .x = x; this .y = y; } toString() { return '(' + this .x + ', ' + this .y + ')' ; } } class ColorPoint extends Point { constructor (x, y, color) { super (x, y); this .color = color; } toString() { return super .toString() + ' in ' + this .color; } }

Again, this class is used like you’d expect:

> let cp = new ColorPoint(25, 8, 'green'); > cp.toString() '(25, 8) in green' > cp instanceof ColorPoint true > cp instanceof Point true

There are two kinds of classes:

Point is a base class, because it doesn’t have an extends clause.

is a base class, because it doesn’t have an clause. ColorPoint is a derived class.

There are two ways of using super :

A class constructor (the pseudo-method constructor in a class literal) uses it like a function call ( super(···) ), in order to make a super-constructor call (line A).

in a class literal) uses it like a function call ( ), in order to make a super-constructor call (line A). Method definitions (in object literals or classes, with or without static ) use it like property references ( super.prop ) or method calls ( super.method(···) ), in order to refer to super-properties (line B).

The prototype of a subclass is the superclass #

The prototype of a subclass is the superclass in ECMAScript 6:

> Object.getPrototypeOf(ColorPoint) === Point true

That means that static properties are inherited:

class Foo { static classMethod() { return 'hello' ; } } class Bar extends Foo { } Bar.classMethod();

You can even super-call static methods:

class Foo { static classMethod() { return 'hello' ; } } class Bar extends Foo { static classMethod() { return super .classMethod() + ', too' ; } } Bar.classMethod();

In a derived class, you must call super() before you can use this :

class Foo {} class Bar extends Foo { constructor (num) { let tmp = num * 2 ; this .num = num; super (); this .num = num; } }

Implicitly leaving a derived constructor without calling super() also causes an error:

class Foo {} class Bar extends Foo { constructor () { } } let bar = new Bar();

Overriding the result of a constructor #

Just like in ES5, you can override the result of a constructor by explicitly returning an object:

class Foo { constructor () { return Object .create( null ); } } console .log( new Foo() instanceof Foo);

If you do so, it doesn’t matter whether this has been initialized or not. In other words: you don’t have to call super() in a derived constructor if you override the result in this manner.

Default constructors for classes #

If you don’t specify a constructor for a base class, the following definition is used:

constructor () {}

For derived classes, the following default constructor is used:

constructor (...args) { super (...args); }

Subclassing built-in constructors #

In ECMAScript 6, you can finally subclass all built-in constructors (there are work-arounds for ES5, but these have significant limitations).

For example, you can now create your own exception classes (that will inherit the feature of having a stack trace in most engines):

class MyError extends Error { } throw new MyError( 'Something happened!' );

You can also create subclasses of Array whose instances properly handle length :

class MyArray extends Array { constructor (len) { super (len); } } let myArr = new MyArray( 0 ); console .log(myArr.length); myArr[ 0 ] = 'foo' ; console .log(myArr.length);

Note that subclassing built-in constructors is something that engines have to support natively, you won’t get this feature via transpilers.

The details of classes #

What we have seen so far are the essentials of classes. You only need to read on if you are interested how things happen under the hood. Let’s start with the syntax of classes. The following is a slightly modified version of the syntax shown in Sect. A.4 of the ECMAScript 6 specification.

ClassDeclaration: "class" BindingIdentifier ClassTail ClassExpression: "class" BindingIdentifier? ClassTail ClassTail: ClassHeritage? "{" ClassBody? "}" ClassHeritage: "extends" AssignmentExpression ClassBody: ClassElement+ ClassElement: MethodDefinition "static" MethodDefinition ";" MethodDefinition: PropName "(" FormalParams ")" "{" FuncBody "}" "*" PropName "(" FormalParams ")" "{" GeneratorBody "}" "get" PropName "(" ")" "{" FuncBody "}" "set" PropName "(" PropSetParams ")" "{" FuncBody "}" PropertyName: LiteralPropertyName ComputedPropertyName LiteralPropertyName: IdentifierName /* foo */ StringLiteral /* "foo" */ NumericLiteral /* 123.45, 0xFF */ ComputedPropertyName: "[" Expression "]"

Two observations:

The value to be extended can be produced by an arbitrary expression. Which means that you’ll be able to write code such as the following: class Foo extends combine ( MyMixin , MySuperClass ) {}

Semicolons are allowed between methods.

Various checks #

Error checks: the class name cannot be eval or arguments ; duplicate class element names are not allowed; the name constructor can only be used for a normal method, not for a getter, a setter or a generator method.

Classes can’t be function-called. They throw a TypeException if they are.

Prototype methods cannot be used as constructors: class C { m() {} } new C.prototype.m();

Attributes of properties #

Class declarations create (mutable) let bindings. For a given class Foo :

Static methods Foo.* are writable and configurable, but not enumerable. Making them writable allows for dynamic patching.

are writable and configurable, but not enumerable. Making them writable allows for dynamic patching. A constructor and the object in its property prototype have an immutable link: Foo.prototype is non-writeable, non-enumerable, non-configurable. Foo.prototype.constructor is non-writeable, non-enumerable, non-configurable.

have an immutable link: Prototype methods Foo.prototype.* are writable and configurable, but not enumerable.

Note that method definitions in object literals produce enumerable properties.

The details of subclassing #

In ECMAScript 6, subclassing looks as follows.

class Point { constructor (x, y) { this .x = x; this .y = y; } ··· } class ColorPoint extends Point { constructor (x, y, color) { super (x, y); this .color = color; } ··· } let cp = new ColorPoint( 25 , 8 , 'green' );

This code produces the following objects.

The next subsection examines the prototype chains (in the two columns), the subsection after that examines how cp is allocated and initialized.

Prototype chains #

In the diagram, you can see that there are two prototype chains (objects linked via the [[Prototype]] relationship, which is an inheritance relationship):

Left column: classes (functions). The prototype of a derived class is the class it extends. The prototype of a base class is Function.prototype , which is also the prototype of functions: > const getProto = Object.getPrototypeOf.bind(Object); > getProto(Point) === Function.prototype true > getProto(function () {}) === Function.prototype true

Right column: the prototype chain of the instance. The whole purpose of a class is to set up this prototype chain. The prototype chain ends with Object.prototype (whose prototype is null ), which is also the prototype of objects created via object literals: > const getProto = Object.getPrototypeOf.bind(Object); > getProto(Point.prototype) === Object.prototype true > getProto({}) === Object.prototype true

The prototype chain in the left column leads to static properties being inherited.

Allocating and initializing the instance object #

The data flow between class constructors is different from the canonical way of subclassing in ES5. Under the hood, it roughly looks as follows.

function Point ( x, y ) { this = Object .create( new .target.prototype); this .x = x; this .y = y; } ··· function ColorPoint ( x, y, color ) { this = uninitialized; this = Reflect .construct(Point, [x, y], new .target); this .color = color; } Object .setPrototypeOf(ColorPoint, Point); ··· let cp = Reflect .construct( ColorPoint, [ 25 , 8 , 'green' ], ColorPoint);

The instance object is created in different locations in ES6 and ES5:

In ES6, it is created in the base constructor, the last in a chain of constructor calls.

In ES5, it is created in the operand of new , the first in a chain of constructor calls.

The previous code uses two new ES6 features:

new.target is an implicit parameter that all functions have. It is to constructor calls what this is to method calls. If a constructor has been directly invoked via new , its value is that constructor (line B). If a constructor was called via super() , its value is the new.target of the constructor that made the call (line A). During a normal function call, it is undefined . That means that you can use new.target to determine whether a function was function-called or constructor-called (via new ). Inside an arrow function, new.target refers to the new.target of the surrounding non-arrow function.

Reflect.construct() lets you do a constructor call while specifying new.target via the last parameter.

The advantage of this way of subclassing is that it enables normal code to subclass built-in constructors (such as Error and Array ). A later section explains why a different approach was necessary.

Safety checks #

this originally being uninitialized in derived constructors means that an error is thrown if they access this in any way before they have called super() .

originally being uninitialized in derived constructors means that an error is thrown if they access in any way before they have called . Once this is initialized, calling super() produces a ReferenceError . This protects you against calling super() twice.

is initialized, calling produces a . This protects you against calling twice. If a constructor returns implicitly (without a return statement), the result is this . If this is uninitialized, a ReferenceError is thrown. This protects you against forgetting to call super() .

statement), the result is . If is uninitialized, a is thrown. This protects you against forgetting to call . If a constructor explicitly returns a non-object (including undefined and null ), the result is this (this behavior is required to remain compatible with ES5 and earlier). If this is uninitialized, a TypeError is thrown.

and ), the result is (this behavior is required to remain compatible with ES5 and earlier). If is uninitialized, a is thrown. If a constructor explicitly returns an object, it is used as its result. Then it doesn’t matter whether this is initialized or not.

The extends clause #

Let’s examine how the extends clause influences how a class is set up (Sect. 14.5.14 of the spec).

The value of an extends clause must be “constructible” (invocable via new ). null is allowed, though.

class C { }

Constructor kind: base

Prototype of C : Function.prototype (like a normal function)

: (like a normal function) Prototype of C.prototype : Object.prototype (which is also the prototype of objects created via object literals)

class C extends B { }

Constructor kind: derived

Prototype of C : B

: Prototype of C.prototype : B.prototype

class C extends Object { }

Constructor kind: derived

Prototype of C : Object

: Prototype of C.prototype : Object.prototype

Note the following subtle difference with the first case: If there is no extends clause, the class is a base class and allocates instances. If a class extends Object , it is a derived class and Object allocates the instances. The resulting instances (including their prototype chains) are the same, but you get there differently.

class C extends null { }

Constructor kind: derived

Prototype of C : Function.prototype

: Prototype of C.prototype : null

Such a class is not very useful: new -calling it leads to an error, because the default constructor makes a super-constructor call and Function.prototype (the super-constructor) can’t be constructor-called. The only way to make the error go away is by adding a constructor that returns an object.

Why can’t you subclass built-in constructors in ES5? #

In ECMAScript 5, most built-in constructors can’t be subclassed (several work-arounds exist).

To understand why, let’s use the canonical ES5 pattern to subclass Array . As we shall soon find out, this doesn’t work.

function MyArray ( len ) { Array .call( this , len); } MyArray.prototype = Object .create( Array .prototype);

Unfortunately, if we instantiate MyArray , we find out that it doesn’t work properly: The instance property length does not change in reaction to us adding array elements:

> var myArr = new MyArray(0); > myArr.length 0 > myArr[0] = 'foo'; > myArr.length 0

There are two obstracles that prevent myArr from being a proper array.

First obstacle: initialization. The this you hand to the constructor Array (in line A) is completely ignored. That means you can’t use Array to set up the instance that was created for MyArray .

> var a = []; > var b = Array.call(a, 3); > a !== b // a is ignored, b is a new object true > b.length // set up correctly 3 > a.length // unchanged 0

Second obstacle: allocation. The instance objects created by Array are exotic (a term used by the ECMAScript specification for objects that have features that normal objects don’t have): Their property length tracks and influences the management of array elements. In general, exotic objects can be created from scratch, but you can’t convert an existing normal object into an exotic one. Unfortunately, that is what Array would have to do, when called in line A: It would have to turn the normal object created for MyArray into an exotic array object.

The solution: ES6 subclassing #

In ECMAScript 6, subclassing Array looks as follows:

class MyArray extends Array { constructor (len) { super (len); } }

This works (but it’s not something that ES6 transpilers can support, it depends on whether a JavaScript engine supports it natively):

> let myArr = new MyArray(0); > myArr.length 0 > myArr[0] = 'foo'; > myArr.length 1

We can now see how the ES6 approach to subclassing circumvents the obstacles:

Allocation happens in the base constructor, which means that Array can allocate an exotic object. While most of the new approach is due to how derived constructors behave, this step requires that a base constructor is aware of new.target and makes new.target.prototype the protoype of the allocated instance.

can allocate an exotic object. While most of the new approach is due to how derived constructors behave, this step requires that a base constructor is aware of and makes the protoype of the allocated instance. Initialization also happens in the base constructor, a derived constructor receives an initialized object and works with that one instead of passing its own instance to the super-constructor and requiring it to set it up.

Referring to super-properties in methods #

The following ES6 code makes a super-method call in line B.

class Point { constructor (x, y) { this .x = x; this .y = y; } toString() { return '(' + this .x + ', ' + this .y + ')' ; } } class ColorPoint extends Point { constructor (x, y, color) { super (x, y); this .color = color; } toString() { return super .toString() + ' in ' + this .color; } } let cp = new ColorPoint( 25 , 8 , 'green' ); console .log(cp.toString());

To understand how super-calls work, let’s look at the object diagram of cp :

ColorPoint.prototype.toString makes a super-call (line B) to the method (starting in line A) that it has overridden. Let’s call the object, in which a method is stored, the home object of that method. For example, ColorPoint.prototype is the home object of ColorPoint.prototype.toString() .

The super-call in line B involves three steps:

Start your search in the prototype of the home object of the current method. Look for a method whose name is toString . That method may be found in the object where the search started or later in the prototype chain. Call that method with the current this . The reason for doing so is: the super-called method must be able to access the same instance properties (in our example, the properties of cp ).

Note that even if you are only getting or setting a property (not calling a method), you still have to consider this in step #3, because the property may be implemented via a getter or a setter.

Let’s express these steps in three different, but equivalent, ways:

var result = Point.prototype.toString.call( this ) var superObject = Point.prototype; var superMethod = superObject.toString; var result = superMethod.call( this ) var homeObject = ColorPoint.prototype; var superObject = Object .getPrototypeOf(homeObject); var superMethod = superObject.toString; var result = superMethod.call( this )

Variation 3 is how ECMAScript 6 handles super-calls. This approach is supported by two internal bindings that the environments of functions have (environments provide storage space, so-called bindings, for the variables in a scope):

[[thisValue]] : This internal binding also exists in ECMAScript 5 and stores the value of this .

: This internal binding also exists in ECMAScript 5 and stores the value of . [[HomeObject]] : Refers to the home object of the environment’s function. Filled in via an internal property [[HomeObject]] that all methods have that use super . Both the binding and the property are new in ECMAScript 6.

A method definition in a class literal that uses super is now special: Its value is still a function, but it has the internal property [[HomeObject]] . That property is set up by the method definition and can’t be changed in JavaScript. Therefore, you can’t meaningfully move such a method to a different object.

Using super to refer to a property is not allowed in function declarations, function expressions and generator functions.

Referring to super-properties is handy whenever prototype chains are involved, which is why you can use it in method definitions inside object literals and class literals (the class can be derived or not, the method can be static or not).

Constructor calls explained via JavaScript code #

The JavaScript code in this section is a much simplified version of how the specification describes constructor calls and super-constructor calls. It may be interesting to you if you prefer code to explanations in human language. Before we can delve into the actual functionality, we need to understand a few other mechanisms.

Internal variables and properties #

The specification writes internal variables and properties in double brackets ( [[Foo]] ). In the code, I use double underscores, instead ( __Foo__ ).

Internal variables used in the code:

[[NewTarget]] : The operand of the new operator that triggered the current constructor call (passed on if [[Construct]] is called recursively via super() ).

: The operand of the operator that triggered the current constructor call (passed on if is called recursively via ). [[thisValue]] : Stores the value of this .

: Stores the value of . [[FunctionObject]] : Refers to the function that is currently executed.

Internal properties used in the code:

[[Construct]] : All constructor functions (including those created by classes) have this own (non-inherited) method. It implements constructor calls and is invoked by new .

: All constructor functions (including those created by classes) have this own (non-inherited) method. It implements constructor calls and is invoked by . [[ConstructorKind]] : A property of constructor functions whose value is either 'base' or 'derived' .

Environments provide storage space for variables, there is one environment per scope. Environments are managed as a stack. The environment on top of that stack is considered active. The following code is a sketch of how environments are handled.

class FunctionEnvironment extends Environment { constructor (Func) { this .__FunctionObject__ = Func; } } function PushEnvironment ( env ) { ··· } function PopEnvironment ( ) { ··· } function GetThisEnvironment ( ) { ··· }

Constructor calls #

Let’s start with the default way (ES6 spec Sect. 9.2.3) in which constructor calls are handled for functions:

AnyFunction.__Construct__ = function ( args, newTarget ) { let Constr = this ; let kind = Constr.__ConstructorKind__; let env = new FunctionEnvironment(Constr); env.__NewTarget__ = newTarget; if (kind === 'base' ) { env.__thisValue__ = Object .create(newTarget.prototype); } else { env.__thisValue__ = uninitialized; } PushEnvironment(env); let result = Constr(...args); PopEnvironment(); if (WasExplicitlyReturned(result)) { if (isObject(result)) { return result; } if (kind === 'base' ) { return env.__thisValue__; } throw new TypeError (); } if (env.__thisValue__ === uninitialized) { throw new ReferenceError (); } return env.__thisValue__; }

Super-constructor calls are handled as follows (ES6 spec Sect. 12.3.5.1).

function super ( ...args ) { let env = GetThisEnvironment(); let newTarget = env.__NewTarget__; let activeFunc = env.__FunctionObject__; let superConstructor = Object .getPrototypeOf(activeFunc); env.__thisValue__ = superConstructor .__Construct__(args, newTarget); }

The species pattern #

One more mechanism of built-in constructors has been made extensible in ECMAScript 6: If a method such as Array.prototype.map() returns a fresh instance, what constructor should it use to create that instance? The default is to use the same constructor that created this , but some subclasses may want it to remain a direct instance of Array . ES6 lets subclasses override the default, via the so-called species pattern:

When creating a new instance of Array , methods such as map() use the constructor stored in this.constructor[Symbol.species] .

, methods such as use the constructor stored in . If a sub-constructor of Array does nothing, it inherits Array[Symbol.species] . That property is a getter that returns this .

You can override the default, via a static getter (line A):

class MyArray1 extends Array { } let result1 = new MyArray1().map( x => x); console .log(result1 instanceof MyArray1); class MyArray2 extends Array { static get [Symbol.species]() { return Array ; } } let result2 = new MyArray2().map( x => x); console .log(result2 instanceof MyArray2);

An alternative is to use Object.defineProperty() (you can’t use assignment, as that would trigger a setter, which doesn’t exist):

Object .defineProperty( MyArray2, Symbol .species, { value : Array });

The following getters all return this , which means that methods such as Array.prototype.map() use the constructor that created the current instance for their results.

Array.get [Symbol.species]()

ArrayBuffer.get [Symbol.species]()

Map.get [Symbol.species]()

Promise.get [Symbol.species]()

RegExp.get [Symbol.species]()

Set.get [Symbol.species]()

%TypedArray%.get [Symbol.species]()

The specialization of functions #

There is an interesting trend in ECMAScript 6: Previously, a single kind of function took on three roles: real function, method and constructor. In ES6, there is specialization:

Arrow functions are specialized for non-method callbacks, where them picking up the this of their surrounding method or constructor is an advantage. Without this , they don’t make much sense as methods and they throw an exception when invoked via new .

Method definitions enable the use of super , by setting up the property [[HomeObject]] . The functions they produce can’t be constructor-called.

Class definitions are the only way to create derived constructors (enabling ES6-style subclassing that works for built-in constructors). Class definitions produce functions that can only be constructor-called.

The future of classes #

The design maxim for classes was “maximally minimal”. Several advanced features were discussed, but ultimately discarded in order to get a design that would be unanimously accepted by TC39.

Upcoming versions of ECMAScript can now extend this minimal design – classes will provide a foundation for features such as traits (or mixins), value objects (where different objects are equal if they have the same content) and const classes (that produce immutable instances).

Does JavaScript need classes? #

Classes are controversial within the JavaScript community. On one hand, people coming from class-based languages are happy that they don’t have to deal with JavaScript’s unorthodox inheritance mechanisms, anymore. On the other hand, there are many JavaScript programmers who argue that what’s complicated about JavaScript is not prototypal inheritance, but constructors .

ES6 classes provide a few clear benefits:

They are backwards compatible with much of the current code.

Compared to constructors and constructor inheritance, classes make it easier for beginners to get started.

Subclassing is supported within the language.

Built-in constructors are subclassable.

No library for inheritance is needed, anymore; code will become more portable between frameworks.

They provide a foundation for advanced features in the future (mixins and more).

They help tools that statically analyze code (IDEs, type checkers, style checkers, etc.).

I have made my peace with classes and am glad that they are in ES6. I would have preferred them to be prototypal (based on constructor objects , not constructor functions), but I also understand that backwards compatibility is important.

Further reading #

Acknowledgement: #1 was an important source of this blog post.